Как представить число в другой системе счисления?
Как представить число в другой системе счисления?
function BaseConvert(NumIn: string; BaseIn: Byte; BaseOut: Byte): string;
var
i: integer;
currentCharacter: char;
CharacterValue: Integer;
PlaceValue: Integer;
RunningTotal: Double;
Remainder: Double;
BaseOutDouble: Double;
NumInCaps: string;
s: string;
begin
if (NumIn = '') or (BaseIn < 2) or (BaseIn > 36) or (BaseOut < 1) or (BaseOut > 36) then
begin
Result := 'Error';
Exit;
end;
NumInCaps := UpperCase(NumIn);
PlaceValue := Length(NumInCaps);
RunningTotal := 0;
for i := 1 to Length(NumInCaps) do
begin
PlaceValue := PlaceValue - 1;
CurrentCharacter := NumInCaps[i];
CharacterValue := 0;
if (Ord(CurrentCharacter) > 64) and (Ord(CurrentCharacter) < 91) then
CharacterValue := Ord(CurrentCharacter) - 55;
if CharacterValue = 0 then
if (Ord(CurrentCharacter) < 48) or (Ord(CurrentCharacter) > 57) then
begin
BaseConvert := 'Error';
Exit;
end
else
CharacterValue := Ord(CurrentCharacter);
if (CharacterValue < 0) or (CharacterValue > BaseIn - 1) then
begin
BaseConvert := 'Error';
Exit;
end;
RunningTotal := RunningTotal + CharacterValue * (Power(BaseIn, PlaceValue));
end;
while RunningTotal > 0 do
begin
BaseOutDouble := BaseOut;
Remainder := RunningTotal - (int(RunningTotal / BaseOutDouble) * BaseOutDouble);
RunningTotal := (RunningTotal - Remainder) / BaseOut;
if Remainder >= 10 then
CurrentCharacter := Chr(Trunc(Remainder + 55))
else
begin
s := IntToStr(trunc(remainder));
CurrentCharacter := s[Length(s)];
end;
Result := CurrentCharacter + Result;
end;
end;
// Example, Beispiel
procedure TForm1.Button1Click(Sender: TObject);
begin
BaseConvert('FFFF', 16, 10);
// returns, ergibt '65535'.
end;
Взято с сайта
Решение от Борланд:
The following function will convert a number from one base to
a number of another base:
procedure RadixStr(NumStr : pChar;
Radix : LongInt;
ResultStr : pChar;
NewRadix : LongInt;
var ErrorCode : LongInt);
The RadixStr() function takes a pointer to a null terminated string
containing a number of one base, and fills a buffer with a null
terminated string containing the number converted to another base.
Parameters:
NumStr: A pointer to a null terminated string containing the numeric
string to convert:
Radix: The base of the number contained in the NumStr parameter. The
base must be in the range of 2 to 36;
ResultStr : A pointer to a null terminated string buffer to place the
resulting numeric string. The buffer should be sufficiently large to
hold the resulting string.
NewRadix: The base to use in the conversion. The base must be in the
range of 2 to 36;
ErrorCode: Upon return, contains the return code 0 if successful, or
the character number of the offending character contained in the
buffer NumStr.
Examples of calling the RadixStr() function:
{Convert Hex to Decimal}
RadixStr('FF',
16,
lpBuffer,
10,
Code);
Should return the string '255' in lpbuffer^.
{Convert Decimal to Binary}
RadixStr('255',
10,
lpBuffer,
2,
Code);
Should return the string '11111111' in lpbuffer^.
{Convert Hex to Octal}
RadixStr('FF',
16,
lpBuffer,
8,
Code);
Should return the string '377' in lpbuffer^.
{Function code}
procedure RadixStr(NumStr : pChar;
Radix : LongInt;
ResultStr : pChar;
NewRadix : LongInt;
var ErrorCode : LongInt);
var
RadixChar : array[0..35] of Char;
v : LongInt;
i : LongInt;
p : LongInt;
c : Integer;
begin
if ((Abs(Radix) < 2) or
(Abs(Radix) > 36)) then begin
ErrorCode := p;
Exit;
end;
StrLCopy(ResultStr, NumStr, StrLen(NumStr));
for i := 0 to 35 do begin
if i <= 9 then
RadixChar[i] := Char(48 + (i))
else
RadixChar[i] := Char(64 + (i - 9))
end;
v := 0;
for i := 0 to (StrLen(ResultStr) - 1) do begin
ResultStr[i] := UpCase(ResultStr[i]);
p := Pos(ResultStr[i], PChar(@RadixChar)) - 1;
if ((p < 0) or
(p >= Abs(Radix))) then begin
ErrorCode := i;
Exit;
end;
v := v * Abs(Radix) + p;
end;
if v = 0 then begin
ResultStr := '0';
ErrorCode := 0;
exit;
end else begin
i:=0;
repeat
ResultStr[i] := RadixChar[v mod NewRadix];
v := v div NewRadix;
Inc(i)
until v = 0;
if Radix < 0 then begin
ResultStr[i] := '-';
ResultStr[i + 1] := #0
end else
ResultStr[i] := #0;
p := StrLen(ResultStr);
for i := 0 to ((p div 2) - 1) do begin
ResultStr[i] := Char(Byte(ResultStr[i]) xor
Byte(ResultStr[(p - i) - 1]));
ResultStr[(p - i) - 1] := Char(Byte(ResultStr[(p - i) - 1]) xor
Byte(ResultStr[i]));
ResultStr[i] := Char(Byte(ResultStr[i]) xor
Byte(ResultStr[(p - i) - 1]))
end;
ResultStr[p] := #0;
ErrorCode := 0;
end;
end;